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Path-Resource-0.072
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/ Path::Resource

NAME

Path::Resource - URI/Path::Class combination

VERSION

Version 0.072

SYNOPSIS


            

              
              
use Path::Resource;
# Map a resource on the local disk to a URI.
# Its (disk) directory is "/var/dir" and its uri is "http://hostname/loc"
my $rsc = new Path::Resource dir => "/var/dir", uri => "http://hostname/loc";
# uri: http://hostname/loc 
# dir: /var/dir
my $apple_rsc = $rsc->child("apple");
# uri: http://hostname/loc/apple
# dir: /var/dir/apple
my $banana_txt_rsc = $apple_rsc->child("banana.txt");
# uri: http://hostname/loc/apple/banana.txt
# file: /var/dir/apple/banana.txt
my $size = -s $banana_txt_rsc->file;
redirect($banana_txt_rsc->uri);
# Redirect to "http://hostname/loc/apple/banana.txt"

DESCRIPTION

Path::Resource is a module for combining local file and directory manipulation with URI manipulation. It allows you to effortlessly map local file locations to their URI equivalent.

It combines Path::Class and URI into one object.

Given a base Path::Resource, you can descend (using ->child) or ascend (using ->parent) the path tree while maintaining URI equivalency, all in one object.

As a convenience, if you do not need the full URI, you can use the ->loc method to just return the URI path.

METHODS

$rsc = Path::Resource->new
$rsc = Path::Resource->new( dir => $dir, uri => $uri, [ path => $path ] )

Create and return a new Path::Resource object using $dir as the base dir and $uri as the base uri.

The URI path of $uri will be automatically extracted and used as the base loc.

If $path is given, then the $rsc will start at that point on the path.


            

              
              
# For example, if the following $rsc is created like so:
my $rsc = Path::Resource->new(uri => "http://example.com/a", dir => "/home/b/htdocs", path => "xyzzy");
my $dir = $rsc->dir; # The dir "/home/b/htdocs/xyzzy"
my $uri = $rsc->uri; # The uri "http://example.com/a/xyzzy"
# Note that path doesn't have to be a dir.
# You can give it a file path if you like (Path::Resource doesn't care)
$rsc = Path::Resource->new(uri => "http://example.com/a", dir => "/home/b/htdocs", path => "xyzzy/nothing.txt");
my $file = $rsc->file; # The file "/home/b/htdocs/xyzzy/nothing.txt"
$uri = $rsc->uri; # The uri "http://example.com/a/xyzzy/nothing.txt"
$rsc = Path::Resource->new( dir => $dir, uri => $uri, loc => $loc, [ path => $path ] )

Create and return a new Path::Resource object using $dir as the base dir, $uri as the base uri, and using $loc as the base loc (the uri path).

If $loc is relative, then it will be appended to $uri->path, otherwise (being absolute) it will replace $uri->path.

If $path is given, then the $rsc will start at that point on the path.


            

              
              
# For example, if the following $rsc is created like so:
my $rsc = Path::Resource->new(uri => "http://example.com/a", dir => "/home/b/htdocs", loc => "c");
my $dir = $rsc->dir; # The dir "/home/b/htdocs"
my $uri = $rsc->uri; # The uri "http://example.com/a/c"
# On the other hand:
$rsc = Path::Resource->new(uri => "http://example.com/a", dir => "/home/b/htdocs", loc => "/g/h");
$dir = $rsc->dir; # The dir "/home/b/htdocs"
$uri = $rsc->uri; # The uri "http://example.com/g/h
$rsc = Path::Resource->new( file => $file, dir => $dir, uri => $uri, [ loc => $loc, path => $path ] )

Create and return a new Path::Resource object using $dir as the base dir, $uri as the base uri, and the difference between $file and $dir as the path (literally: $path = $file->relative($dir))

If $loc is given then if it is relative, then it will be appended to $uri->path, otherwise (being absolute) it will replace $uri->path.

$rsc->path
$rsc->path( <part>, [ <part>, ..., <part> ] )

Return a clone of $rsc->path based on $rsc->path and any optional <part> passed through


            

              
              
my $rsc = Path::Resource->new(path => "b/c");
# $path is "b/c"
my $path = $rsc->path;
# $path is "b/c/d"
my $path = $rsc->path("d");
$rsc->clone
$rsc->clone( <path> )

Return a Path::Resource object that is a copy of $rsc

The optional argument will change (not append) the path of the cloned object

$rsc->subdir( <part>, [ <part>, ..., <part> ] )
$rsc->child( <part>, [ <part>, ..., <part> ] )

Return a clone Path::Resource object whose path is the child of $rsc->path


            

              
              
my $rsc = Path::Resource->new(dir => "/a", path => "b");
# $rsc->path is "b/c/d.tmp"
$rsc = $rsc->child("c/d.tmp");
# ->subdir is an alias for ->child
$rsc = $rsc->parent->subdir("e");
$rsc->parent

Return a clone Path::Resource object whose path is the parent of $rsc->path


            

              
              
my $rsc = Path::Resource->new(dir => "/a", path => "b/c");
# $rsc->path is "b"
$rsc = $rsc->parent;
# $rsc->path is ""
$rsc = $rsc->parent;
# $dir is "/a/f"
my $dir = $rsc->parent->parent->dir("f");
$rsc->loc
$rsc->loc( <part>, [ <part>, ..., <part> ] )

Return a Path::Abstract object based on the path part of $rsc->base->uri ($rsc->base->loc), $rsc->path, and any optional <part> passed through


            

              
              
my $rsc = Path::Resource->new(uri => "http://example.com/a", path => "b/c");
# $loc is "/a/b/c"
my $loc = $rsc->loc;
# $dir is "/a/b/c/d.tmp"
$loc = $rsc->loc("d.tmp");
$rsc->uri
$rsc->uri( <part>, [ <part>, ..., <part> ] )

Return a URI object based on $rsc->base->uri, $rsc->path, and any optional <part> passed through


            

              
              
my $rsc = Path::Resource->new(uri => "http://example.com/a", path => "b/c");
# $uri is "http://example.com/a/b/c"
my $uri = $rsc->uri;
# $uri is "http://example.com/a/b/c/d.tmp"
$uri = $rsc->uri("d.tmp");
# $uri is "https://example.com/a/b/c/d.tmp"
$uri->scheme("https");
$rsc->file
$rsc->file( [ <part>, <part>, ..., <part> ] )

Return a Path::Class::File object based on $rsc->base->dir, $rsc->path, and any optional <part> passed through

NOTE: This method will return a Path::Class::File object, *NOT* a new Path::Resource object (use ->child for that functionality)


            

              
              
my $rsc = Path::Resource->new(dir => "/a", path => "b");
$rsc = $rsc->child("c/d.tmp");
# $file is "/a/b/c/d.tmp"
my $file = $rsc->file;
# $file is "/a/b/c/d.tmp/e.txt"
$file = $rsc->file(qw/ e.txt /);
$rsc->dir
$rsc->dir( <part>, [ <part>, ..., <part> ] )

Return a Path::Class::Dir object based on $rsc->base->dir, $rsc->path, and any optional <part> passed through


            

              
              
my $rsc = Path::Resource->new(dir => "/a", path => "b");
$rsc = $rsc->child("c/d.tmp");
# $dir is "/a/b/c/d.tmp"
my $dir = $rsc->file;
# $dir is "/a/b/c/d.tmp/e.tmp"
$dir = $rsc->file(qw/ e.tmp /);
$rsc->base

Return the Path::Resource::Base object for $rsc

AUTHOR

Robert Krimen, <rkrimen at cpan.org>

SEE ALSO

URI::ToDisk

BUGS

Please report any bugs or feature requests to bug-path-resource at rt.cpan.org, or through the web interface at http://rt.cpan.org/NoAuth/ReportBug.html?Queue=Path-Resource. I will be notified, and then you'll automatically be notified of progress on your bug as I make changes.

SUPPORT

You can find documentation for this module with the perldoc command.


            

              
              
perldoc Path::Resource

You can also look for information at:

ACKNOWLEDGEMENTS

COPYRIGHT & LICENSE

Copyright 2007 Robert Krimen, all rights reserved.

This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.