=head1 NAME
perllol - Manipulating Arrays of Arrays in Perl
=head1 DESCRIPTION
=head2 Declaration and Access of Arrays of Arrays
The simplest two-level data structure to build in Perl is an array of
arrays, sometimes casually called a list of lists. It's reasonably easy to
understand, and almost everything that applies here will also be applicable
later on
with
the fancier data structures.
An array of an array is just a regular old array
@AoA
that you can
get at
with
two subscripts, like C<
$AoA
[3][2]>. Here's a declaration
of the array:
@AoA
= (
[
"fred"
,
"barney"
,
"pebbles"
,
"bambam"
,
"dino"
, ],
[
"george"
,
"jane"
,
"elroy"
,
"judy"
, ],
[
"homer"
,
"bart"
,
"marge"
,
"maggie"
, ],
);
say
$AoA
[2][1];
bart
Now you should be very careful that the outer bracket type
is a round one, that is, a parenthesis. That
's because you'
re assigning to
an
@array
, so you need parentheses. If you wanted there I<not> to be an
@AoA
,
but rather just a reference to it, you could
do
something more like this:
$ref_to_AoA
= [
[
"fred"
,
"barney"
,
"pebbles"
,
"bambam"
,
"dino"
, ],
[
"george"
,
"jane"
,
"elroy"
,
"judy"
, ],
[
"homer"
,
"bart"
,
"marge"
,
"maggie"
, ],
];
say
$ref_to_AoA
->[2][1];
bart
Notice that the outer bracket type
has
changed, and so
our
access syntax
has
also changed. That
's because unlike C, in perl you can'
t freely
interchange arrays and references thereto.
$ref_to_AoA
is a reference to an
array, whereas
@AoA
is an array proper. Likewise, C<
$AoA
[2]> is not an
array, but an array
ref
. So how come you can
write
these:
$AoA
[2][2]
$ref_to_AoA
->[2][2]
instead of having to
write
these:
$AoA
[2]->[2]
$ref_to_AoA
->[2]->[2]
Well, that's because the rule is that on adjacent brackets only (whether
square or curly), you are free to omit the pointer dereferencing arrow.
But you cannot
do
so
for
the very first one
if
it's a
scalar
containing
a reference, which means that
$ref_to_AoA
always needs it.
=head2 Growing Your Own
That's all well and good
for
declaration of a fixed data structure,
but what
if
you wanted to add new elements on the fly, or build
it up entirely from scratch?
First, let's look at reading it in from a file. This is something like
adding a row at a
time
. We
'll assume that there'
s a flat file in which
each
line is a row and
each
word an element. If you're trying to develop an
@AoA
array containing all these, here's the right way to
do
that:
while
(<>) {
@tmp
=
split
;
push
@AoA
, [
@tmp
];
}
You might also have loaded that from a function:
for
$i
( 1 .. 10 ) {
$AoA
[
$i
] = [ somefunc(
$i
) ];
}
Or you might have had a temporary variable sitting
around
with
the
array in it.
for
$i
( 1 .. 10 ) {
@tmp
= somefunc(
$i
);
$AoA
[
$i
] = [
@tmp
];
}
It's important you make sure to
use
the C<[ ]> array reference
constructor. That
's because this wouldn'
t work:
$AoA
[
$i
] =
@tmp
;
The reason that doesn't
do
what you want is because assigning a
named array like that to a
scalar
is taking an array in
scalar
context, which means just counts the number of elements in
@tmp
.
If you are running under C<
use
strict> (and
if
you aren't, why in
the world aren
't you?), you'
ll have to add some declarations to
make it happy:
my
(
@AoA
,
@tmp
);
while
(<>) {
@tmp
=
split
;
push
@AoA
, [
@tmp
];
}
Of course, you don't need the temporary array to have a name at all:
while
(<>) {
push
@AoA
, [
split
];
}
You also don't have to
use
push
(). You could just make a direct assignment
if
you knew where you wanted to put it:
my
(
@AoA
,
$i
,
$line
);
for
$i
( 0 .. 10 ) {
$line
= <>;
$AoA
[
$i
] = [
split
" "
,
$line
];
}
or even just
my
(
@AoA
,
$i
);
for
$i
( 0 .. 10 ) {
$AoA
[
$i
] = [
split
" "
, <> ];
}
You should in general be leery of using functions that could
potentially
return
lists in
scalar
context without explicitly stating
such. This would be clearer to the casual reader:
my
(
@AoA
,
$i
);
for
$i
( 0 .. 10 ) {
$AoA
[
$i
] = [
split
" "
,
scalar
(<>) ];
}
If you wanted to have a
$ref_to_AoA
variable as a reference to an array,
you'd have to
do
something like this:
while
(<>) {
push
@$ref_to_AoA
, [
split
];
}
Now you can add new rows. What about adding new columns? If you're
dealing
with
just matrices, it's often easiest to
use
simple assignment:
for
$x
(1 .. 10) {
for
$y
(1 .. 10) {
$AoA
[
$x
][
$y
] = func(
$x
,
$y
);
}
}
for
$x
( 3, 7, 9 ) {
$AoA
[
$x
][20] += func2(
$x
);
}
It doesn't matter whether those elements are already
there or not: it'll gladly create them
for
you, setting
intervening elements to C<
undef
> as need be.
If you wanted just to append to a row, you'd have
to
do
something a bit funnier looking:
push
$AoA
[0]->@*,
"wilma"
,
"betty"
;
=head2 Access and Printing
Now it's
time
to
print
your data structure out. How
are you going to
do
that? Well,
if
you want only one
of the elements, it's trivial:
print
$AoA
[0][0];
If you want to
print
the whole thing, though, you can't
say
print
@AoA
;
because you'll get just references listed, and perl will never
automatically dereference things
for
you. Instead, you have to
roll yourself a loop or two. This prints the whole structure,
using the shell-style
for
() construct to loop across the outer
set of subscripts.
for
$aref
(
@AoA
) {
say
"\t [ @$aref ],"
;
}
If you wanted to keep track of subscripts, you might
do
this:
for
$i
( 0 ..
$#AoA
) {
say
"\t elt $i is [ @{$AoA[$i]} ],"
;
}
or maybe even this. Notice the inner loop.
for
$i
( 0 ..
$#AoA
) {
for
$j
( 0 .. $
say
"elt $i $j is $AoA[$i][$j]"
;
}
}
As you can see, it
's getting a bit complicated. That'
s why
sometimes is easier to take a temporary on your way through:
for
$i
( 0 ..
$#AoA
) {
$aref
=
$AoA
[
$i
];
for
$j
( 0 .. $
say
"elt $i $j is $AoA[$i][$j]"
;
}
}
Hmm... that's still a bit ugly. How about this:
for
$i
( 0 ..
$#AoA
) {
$aref
=
$AoA
[
$i
];
$n
=
@$aref
- 1;
for
$j
( 0 ..
$n
) {
say
"elt $i $j is $AoA[$i][$j]"
;
}
}
When you get tired of writing a custom
print
for
your data structures,
you might look at the standard L<Dumpvalue> or L<Data::Dumper> modules.
The former is what the Perl debugger uses,
while
the latter generates
parsable Perl code. For example:
sub
show(+) {
state
$prettily
= new Dumpvalue::
tick
=>
q(")
,
compactDump
=> 1,
veryCompact
=> 1,
;
dumpValue
$prettily
@_
;
}
my
@AoA
= (
[
"fred"
,
"barney"
],
[
"george"
,
"jane"
,
"elroy"
],
[
"homer"
,
"marge"
,
"bart"
],
);
push
$AoA
[0]->@*,
"wilma"
,
"betty"
;
show
@AoA
;
will
print
out:
0 0..3
"fred"
"barney"
"wilma"
"betty"
1 0..2
"george"
"jane"
"elroy"
2 0..2
"homer"
"marge"
"bart"
Whereas
if
you comment out the two lines I said you might wish to,
then it shows it to you this way instead:
0 ARRAY(0x8031d0)
0
"fred"
1
"barney"
2
"wilma"
3
"betty"
1 ARRAY(0x803d40)
0
"george"
1
"jane"
2
"elroy"
2 ARRAY(0x803e10)
0
"homer"
1
"marge"
2
"bart"
=head2 Slices
If you want to get at a slice (part of a row) in a multidimensional
array, you
're going to have to do some fancy subscripting. That'
s
because
while
we have a nice synonym
for
single elements via the
pointer arrow
for
dereferencing,
no
such convenience
exists
for
slices.
Here
's how to do one operation using a loop. We'
ll assume an
@AoA
variable as
before
.
@part
= ();
$x
= 4;
for
(
$y
= 7;
$y
< 13;
$y
++) {
push
@part
,
$AoA
[
$x
][
$y
];
}
That same loop could be replaced
with
a slice operation:
@part
=
$AoA
[4]->@[ 7..12 ];
Now, what
if
you wanted a I<two-dimensional slice>, such as having
$x
run from 4..8 and
$y
run from 7 to 12? Hmm... here's the simple way:
@newAoA
= ();
for
(
$startx
=
$x
= 4;
$x
<= 8;
$x
++) {
for
(
$starty
=
$y
= 7;
$y
<= 12;
$y
++) {
$newAoA
[
$x
-
$startx
][
$y
-
$starty
] =
$AoA
[
$x
][
$y
];
}
}
We can reduce some of the looping through slices
for
(
$x
= 4;
$x
<= 8;
$x
++) {
push
@newAoA
, [
$AoA
[
$x
]->@[ 7..12 ] ];
}
If you were into Schwartzian Transforms, you would probably
have selected
map
for
that
@newAoA
=
map
{ [
$AoA
[
$_
]->@[ 7..12 ] ] } 4 .. 8;
Although
if
your manager accused you of seeking job security (or rapid
insecurity) through inscrutable code, it would be hard to argue. :-)
If I were you, I'd put that in a function:
@newAoA
= splice_2D( \
@AoA
,
4
=> 8,
7
=> 12 );
sub
splice_2D {
my
$lrr
=
shift
;
my
(
$x_lo
,
$x_hi
,
$y_lo
,
$y_hi
) =
@_
;
return
map
{
[
$lrr
->[
$_
]->@[
$y_lo
..
$y_hi
] ]
}
$x_lo
..
$x_hi
;
}
=head1 SEE ALSO
L<perldata>, L<perlref>, L<perldsc>
=head1 AUTHOR
Tom Christiansen <F<tchrist
@perl
.com>>
Last update: Tue Apr 26 18:30:55 MDT 2011